Jump search techniquealso works for ordered lists. It creates a block and tries to find the element in that block. If the item is not in the block, it shifts the entire block. The block size is based on the size of the list. If the size of the list is n then block size will be √n. After finding a correct block it finds the item using a linear search technique. The jump search lies between linear search and binary search according to its performance.
Example :
Following are the implementation of Jump search into programs
// C program for jhmup Search
#include
#include
using namespace std;
int jumpSearch(int array[], int size, int key) {
int start = 0;
int end = sqrt(size); //the square root of array length
while(array[end] <= key && end < size) {
start = end; //it it is not correct block then shift block
end += sqrt(size);
if(end > size - 1)
end = size; //if right exceeds then bound the range
}
for(int i = start; i> n;
int arr[n]; //create an array of size n
cout << "Enter items: " << endl;
for(int i = 0; i< n; i++) {
cin >> arr[i];
}
cout << "Enter search key to search in the list: ";
cin >> searchKey;
if((loc = jumpSearch(arr, n, searchKey)) >= 0)
cout << "Item found at location: " << loc << endl;
else
cout << "Item is not found in the list." << endl;
}
Code
// Java program to implement Jump Search.
public class JumpSearch
{
public static int jumpSearch(int[] arr, int x)
{
int n = arr.length;
// Finding block size to be jumped
int step = (int)Math.floor(Math.sqrt(n));
// Finding the block where element is
// present (if it is present)
int prev = 0;
while (arr[Math.min(step, n)-1] < x)
{
prev = step;
step += (int)Math.floor(Math.sqrt(n));
if (prev >= n)
return -1;
}
// Doing a linear search for x in block
// beginning with prev.
while (arr[prev] < x)
{
prev++;
// If we reached next block or end of
// array, element is not present.
if (prev == Math.min(step, n))
return -1;
}
// If element is found
if (arr[prev] == x)
return prev;
return -1;
}
// Driver program to test function
public static void main(String [ ] args)
{
int arr[] = { 0, 1, 1, 2, 3, 5, 8, 13, 21,
34, 55, 89, 144, 233, 377, 610};
int x = 55;
// Find the index of 'x' using Jump Search
int index = jumpSearch(arr, x);
// Print the index where 'x' is located
System.out.println("\nNumber " + x +
" is at index " + index);
}
}
Code
# Python3 code to implement Jump Search
import math
def jumpSearch( arr , x , n ):
# Finding block size to be jumped
step = math.sqrt(n)
# Finding the block where element is
# present (if it is present)
prev = 0
while arr[int(min(step, n)-1)] < x:
prev = step
step += math.sqrt(n)
if prev >= n:
return -1
# Doing a linear search for x in
# block beginning with prev.
while arr[int(prev)] < x:
prev += 1
# If we reached next block or end
# of array, element is not present.
if prev == min(step, n):
return -1
# If element is found
if arr[int(prev)] == x:
return prev
return -1
# Driver code to test function
arr = [ 0, 1, 1, 2, 3, 5, 8, 13, 21,
34, 55, 89, 144, 233, 377, 610 ]
x = 55
n = len(arr)
# Find the index of 'x' using Jump Search
index = jumpSearch(arr, x, n)
# Print the index where 'x' is located
print("Number" , x, "is at index" ,"%.0f"%index)
Code
Sample Output
Input:
A sorted list of data:
10 13 15 26 28 50 56 88 94 127 159 356 480 567 689 699 780 850 956 995
The search key 356
Output:
Item found at location: 11
Visualized
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